Gradient.addColorStop((1 / 6) * 5, '#ff00ff')Ĭanvas.getContext('2d').fillStyle = gradientĬanvas.getContext('2d').fillRect(0, 0, canvas.width, canvas.height) Let gradient = canvas.getContext('2d').createLinearGradient(0, 0, canvas.width, 0) Var canvasContext = canvas.getContext('2d') Var canvas = document.getElementById('colorCanvas') Var imgData = canvasContext.getImageData(mouseEvent.offsetX, mouseEvent.offsetY, 1, 1) Īlert('rgba(' + rgba + ', ' + rgba + ', ' + rgba + ', ' + rgba + ')') Image.src = './images/m圜olorPickerImage.png' Image.onload = () => canvasContext.drawImage(image, 0, 0, image.width, image.height) Var canvasContext = canvasEl.getContext('2d') Var canvasEl = document.getElementById('colorCanvas') In your JavaScript, init the canvas with your color-picker image, and listen to click events Give the canvas element border-radius: 50%, this will make the canvas round, so only clicks inside the circle will be fired, and clicks in the edge will be ignored (we will need click event in the next steps). (a more complex colors-wheel probable needed in real application) If you like me, and after a long search of color-picker library, you didn't find a picker that meet your criteria, you can build you color picker, which not take too long as I will demonstrate.įind a Color-Wheel image that will be your picker, for example: Even a simple search on the NPM packages page will return a few hundreds results to pick from. If the Native color picker not meet your criteria, since it has an obsolete look and not look as slick as modern Color-Pickers, you can use one of literally hundreds of color pickers on the web. As mentioned in the previous answers you can use Native HTML color picker element: įor more info see: Option #2 - 3rd party Color Picker

Html colorpicker